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consider <A such that cosA= -5/13

a) in which quadrants could this angle exist?

b)if the sin A is negative which quadrant is the angle?

c) sketch a diagram to represent the angle A in standard position, given that the condition in part b) is true

d) write exact expression for the other two primary trigonometric ratios for the angle?
asked Oct 2, 2014 in CALCULUS by anonymous

2 Answers

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cosA = - 5/13

a) The angle A is exist in second or third quadrant.

 

b) If the sinA is negative

cosA and sinA both are negative then the angle in third quadrant.

 

c) x = 5 , r = 13

From Pythagorean theorem,

r2 - x2 = y2

y = √(r2 - x2)

y = √(132 - 52)

y = √(169 -25)

y = 12

If the side of an angle A in standard position goes through (-5, -12)

 

answered Oct 2, 2014 by david Expert
0 votes

Contd..

Angle A is in third quadrant.

x = 5, y = 12

d) Other primary trigonometric ratios are

sin(A) = y/r

sin(A) = -12/13

tan(A) = y/x

tan(A) = 12/5.

answered Oct 2, 2014 by david Expert

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