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Find the probability the first is even and the second is odd.

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Ten cards are numbered 1 through 10. Two cards are selected (without replacement).

asked Dec 6, 2014 in STATISTICS by anonymous

1 Answer

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From the given data 10 cards are numbered 1 through 10.

Two are selected with out replacement.

There are 5 even cards and 5 odd cards.

Lets consider the ordered samples.

For the event must choose an ordered sample of 2 from 10 cards : |S| = 10p2.

There are 5 chances to select the first card as an even and 5 chances to select the second card as an odd.

For the event to select the first card as an even and the second card as an odd : |D| = 5p1 * 5p1 .

The probability : P(D) = |D| / |S| = (5p1 * 5p1) / 10p2

= (5 * 5) / (10 * 9)

= 5 / 18.

Therefore, the probability the first is even and the second is odd is 5/18.

answered Dec 6, 2014 by lilly Expert

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