Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

777,403 users

More algebra 2 help please?

0 votes
Question 11 (Multiple Choice Worth 1 points)

Which of the following is a factor of x2 – 21x + 110?

x + 11

x – 10

x – 5

None of the above

Question 12 (Multiple Choice Worth 1 points)

Which is a factor of 2x2+ 8x – 90 ?

x + 2

x – 15

x + 9

x – 4

Question 13 (Multiple Choice Worth 1 points)

Identify the degree of the polynomial 6xy2 – xy + 8 + 12y.

3

4

5

6

Question 14 (Multiple Choice Worth 1 points)

Which is not a factor of 12x3 – 82x2 – 14x?

(3x – 2)

(6x + 1)

(x – 7)

2x

Question 15 (Multiple Choice Worth 1 points)

Which of the following is a factor of 48x2 – 26x + 3?

8x – 3

12x – 1

4x – 3

None of the above

Question 16 (Multiple Choice Worth 1 points)

Factor completely 81x2 – 36x + 4

(9x – 2)2

(2x – 9)2

(9x – 2)(9x + 2)

None of the above

Question 17 (Multiple Choice Worth 1 points)

Simplify 3x2(7x2 + 2x – 4)

21x2 + 6x – 12

21x2 + 6x3 – 12x

21x4 + 6x3 – 12x2

21 + 6x – 12x2

Question 18 (Multiple Choice Worth 1 points)

Which of the following is a factor of 64x3 + 343?

4x – 7

16x2 – 28x + 49

16x2 + 56x + 49

None of the above

Question 19 (Multiple Choice Worth 1 points)

Factor completely x2 – 12x + 35

(x + 5)(x – 7)

(x – 5)(x – 7)

(x – 5)(x + 7)

prime

Question 20 (Multiple Choice Worth 1 points)

Simplify (10x2 – 8x – 1) + (4x2 – 8x – 5)

14x2 – 16x + 6

14x2 + 16x + 6

14x2 – 16x – 6

14x2 + 16x – 6
asked May 1, 2013 in ALGEBRA 2 by futai Scholar

11 Answers

0 votes

17) 3x2 (7x2+ 2x - 4)

= 3x2(7x2) + 3x2(2x) + 3x2(- 4)

= 21x4 + 6x3  - 12x2

Option 3 is correct answer.

answered Jul 14, 2014 by david Expert

Related questions

asked Nov 12, 2014 in ALGEBRA 1 by anonymous
asked Sep 21, 2018 in ALGEBRA 2 by anonymous
asked Nov 11, 2014 in PRECALCULUS by anonymous
...