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Help!! algebra math homework?!?

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Find the equation of a line that passes through (2,-2) and (-1,-5). Thanks
asked May 31, 2013 in ALGEBRA 1 by linda Scholar

1 Answer

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Given points (2, -2) and (-1, -5)

Say (x1,y1) = (2, -2)

(x2,y2) = (-1,-5)

Slope m = (y2-y1)/(x2-x1)

m = -5 - (-2)/(-1 -2)

The product of same signs is positive

m = -5 +2/-3

m = -3/-3

m = 1

The equation of line is given by y - y1 = m( x - x1)

y - (-2) = 1( x - 2)

The product of same signs is positive

y + 2 = x- 2

Subtract y + 2 from each side

y + 2 - (y + 2) = x - 2 - (y + 2)

0 = x - 2 -y -2

0 = x - y - 2 - 2

0 = x - y - 4

i.e x - y - 4 = 0

The equation of line is x - y - 4 = 0

 

answered May 31, 2013 by jeevitha Novice

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