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8th grade math extended response question?

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Ben sold some tickets for a basketball game. Adult tickets were $5 and student tickets were $3. Ben collected $180 for the 50 tickets he sold. How many adult and child tickets did he sell?

asked Apr 24, 2013 in ALGEBRA 2 by dkinz Apprentice

1 Answer

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Let x be the number of adult tickets Ben sold.

Let y be the number of child tickets Ben sold.

We know he sold 50 tickets.

Hence, x + y = 50 Ben got $5 per adult ticket and $3 per student ticket.

That's 5*x + 3*y.

He got a total of $180.

Hence, 5x + 3y = 180 Now you have a system of two equations and two unknowns,

you should be able to solve that. From the first equation, y = 50 - x.

Plug that into the second equation to get: 5x + 3*(50 - x) = 180

5x - 3x + 150 = 180

2x = 30

x = 15

And since x + y = 50,

it follows that y = 35. Ben sold 15 adult tickets and 35 child tickets.

answered Apr 24, 2013 by Naren Answers Apprentice

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