Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

777,580 users

Grade 10 Math Help! Assessment Tomorrow!?

0 votes
A rectangle with a perimeter of 180cm is four times longer than it is wide. What are its dimensions?
asked Jun 7, 2013 in ALGEBRA 2 by linda Scholar

1 Answer

0 votes
Given that,

                   Perimeter of a rectangle = 180cm

                   Rectangle is 4 times longer than its width i.e, l=4b

Let us assume that,

                  Length of the rectangle be l

                  Width or breadth of the rectangle be b

                  Perimeter be P

Perimeter P = 2(l+b)     [Where perimeter of the rectangle is 2(length + breadth)]

             => 2l + 2b = 180

             => 2(4b) + 2b = 180       where l=4b

             => 8b +2b =180

             => 10b = 180

             => b = 180/10

             => b =18

Therefore width of the rectangle b =18.

Given that length l = 4b

                          => l = 4(18)

                          => l = 72

Therefore length of the rectangle l =72.

Therefore the dimensions of the rectangle are 72 and 18.
answered Jun 10, 2013 by joly Scholar

Related questions

asked Jun 7, 2014 in ALGEBRA 2 by anonymous
asked Jul 25, 2014 in TRIGONOMETRY by anonymous
asked Jul 20, 2014 in ALGEBRA 2 by anonymous
asked Aug 3, 2017 in ALGEBRA 1 by anonymous
...