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Simplify the following trig expression?

0 votes

(1-sinx)(1-cscx)sinx

asked Jun 17, 2013 in TRIGONOMETRY by anonymous Apprentice

1 Answer

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The expression is (1-sinx)(1-cosecx)sinx

=  [ (1-cosecx) -sinx ( 1-cosecx) ]sinx

=  [ (1-cosecx) -sinx +sinx cosecx ] sinx        ( cosecx = 1/ sinx )

= [ 1- cosecx -sinx +(sinx . 1/ sinx) ] sinx

= [ 1-cosecx -sinx +1 ] sinx

= [ sinx - sinx cosecx - sin2x +sinx

=  sinx - (sinx .1/ sinx) -sin2x +sinx

= sinx -1- sin2x +sinx

=  -(sin2x -2sinx +1)

Therefore the solution is  -( sinx - 1)2.

answered Jun 17, 2013 by goushi Pupil

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