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Simplify the identitity

0 votes

(Cot^2x+1)(Sin^2x+1)

trigonometric-expressions

asked Jun 26, 2013 in TRIGONOMETRY by harvy0496 Apprentice

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1 Answer

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Given that ( cot²x +1) ( sin²x +1)

The pythagorean formula cot²x +1 = csc²x

= (csc²x) (sin²x +1)

= 1/sin²x ( sin²x +1)

= 1 +1+csc²x = 2+cot²x

The solution is 2+cot²x .

answered Jun 26, 2013 by goushi Pupil

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