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6x-3y=15 7x+4y=10 solve using elimination

+1 vote
asked Nov 15, 2017 in ALGEBRA 1 by anonymous

1 Answer

0 votes

System of Equations

6x - 3y  =  15 ---------------->  (1)

7x + 4y  =  10 ----------------> (2)

Multiply Eq (1) with 4, Eq (2) with 3 and add both of them

Eq (1) X 4 =====>  24x - 12y  =  60

Eq (2) X 3 =====>  21x + 12y  =  30

                          ---------------------------------

                               45x  =  90

                                   x  =  90 / 45

                                   x  =  2

Substitute x = 2 in Eq (2)

7(2) + 4y  =  10

14 + 4y  =  10

4y  =  10 - 14

4y  =  -4

y  =  -4/4

y  =  -1

Answer :

The Solutions are x = 2 and y = -1.

answered Sep 28 by homeworkhelp Mentor

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