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What is the equation of the line, in slope-intercept form, that passes through the point (4, -1)

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and is perpendicular to the line whose equation is 2x - y - 7 = 0? 

asked Jul 3, 2013 in ALGEBRA 2 by linda Scholar

1 Answer

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The given line equation is 2x - y - 7 = 0

The general slope - intercept form is y = mx+c

y = 2x -7

Therefore slope m = 2

Any perpendicular line slope is - 1/m = -1/2

The slope intercept form of line equation is

y = mx+c

Substitute x = 4, y = -1 and m = -1/2 in above equation

-1 = (-1/2)(4)+c

-1 = -2+c

Therefore c = 1

Substitute m and c value in equation y = mx+c

y =( -1/2)x+1

The solution is y =( -1/2)x+1.

answered Jul 3, 2013 by goushi Pupil

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