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Solve logarithmic equation

0 votes

3(log_7 x - log_7 2) = 2 log_7 4

asked Dec 28, 2017 in ALGEBRA 2 by anonymous

1 Answer

0 votes

3(log_7 x - log_7 2)   =   2 log_7 4

3[log_7 (x/2)]   =    log_7 (4^2)

log_7 (x/2)^3   =    log_7 (4^2)

Apply anti logarithm

(x/2)^3   =   (4^2)

(x/2)^3   =   16

Apply cube root to each side

[ (x/2)^3 ]^(1/3)   =   [16]^(1/3)

x / 2   =  [16]^(1/3)

x   =  2 [16]^(1/3)

 

answered Dec 28, 2017 by homeworkhelp Mentor

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