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solve the equation

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3x^2-4x+5=0
asked Oct 13 in ALGEBRA 2 by anonymous

1 Answer

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The Quadratic Equation

3x^2 - 4x + 5  =  0

Compare it to quadratic form ax^2 + bx  =  0

a = 3, b = -4, c = 5

Roots are  

x  =  [ - ± √(b^2 - 4ac) ] / 2a

 =  [ - (-4) ± √((-4)^2 - 4(3)(5)) ] / 2(3)

 =  [ 4  ± √(16 - 60) ] / 6

 =  [ 4  ± √(-44) ] / 6

 =  [ 4  ± 2i√11 ] / 6

 =  [ 4  + 2i√11 ] / 6          ;        =  [ 4  - 2i√11 ] / 6

 =  4/6  + (2i√11/6            ;        =   4/6  -  (2i√11)/6

 =  2/3  + i(2/3)√11          ;        =   2/3  -  i(2/3)√11

Answer :

The Solutions are x  =  2/3  + i(2/3)√11  and   =  2/3  -  i(2/3)√11.

answered Oct 13 by homeworkhelp Mentor

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