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loga xy^3=9; loga x^2y=8

0 votes

Find value of loga (xy)^(1/2)

asked Jul 20, 2013 in ALGEBRA 1 by futai Scholar

1 Answer

0 votes


logx+3logy=9
2logx+logy=8
logx=a
logy=b
a+3b=9
2a+b=8
solve above equations
b=2 and a=3
1/2(a+b)=1/2(2+3)
1/2(logx+logy)=5/2
log(xy)^1/2=5/2


 

answered Jul 20, 2013 by bradely Mentor
edited Jul 20, 2013 by bradely

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