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finding perpendicular line of y=x+4 passing through (-7,1)

asked Jul 28, 2013 in ALGEBRA 2 by andrew Scholar

1 Answer

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Slope of the given line is 1

The slope of the perpendicular line = -1.

(x1,y1) = (-7,1).

The equation of perpendicular line is,

y-y1=m(x-x1)

y-1= -1(x+7)

y-1 = -x-7

x + y +6 =0

So the required equation of the perpendicular line is, x+y +6=0

answered Jul 28, 2013 by bradely Mentor

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