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Solve using the substitution method

0 votes
Show your work. -8x ?

4y = -68, x + 3y = 16
asked Nov 2, 2013 in ALGEBRA 1 by skylar Apprentice

2 Answers

0 votes

Given eqations are x+3y = 16

4y = -68

now 4y =- 68

Apply division property,divide by 4 to each side.

4y/4 = -68/4

y = -17

Substitute the value of y in x+3y = 16

x+3(-17) = 16

x-51 = 16

Apply addition property, add 51 to each side.

x-51+51 = 16+51

x = 67

check

Substitute the x,y value in x+3y = 16

67+3*-17 = 16

67-51 = 16

16 = 16    and

-8X = -8*67 =-536

answered Nov 2, 2013 by william Mentor
0 votes

using the substitution method.

4y = -68

divide each side by 4.

y = -68/4 = -17

substitute y = -17 in x + 3y = 16.

x + 3 * -17 = 16

x - 51 = 16

Add 51 to each side.

x = 16 + 51 = 67

now, -8x = -8 * 67 = -536.

answered Nov 2, 2013 by rob Pupil

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