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Verify the identity: (sinx + tanx + tan^3x)/tanx = cosx + sec^2x

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Verify identities showing steps

 

asked Nov 20, 2013 in TRIGONOMETRY by homeworkhelp Mentor

1 Answer

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We know that sec^2x-tan^2x = 1

cotx = 1/tanx

Left hand side

= (sinx+tanx+tan^3x)/tanx

= sinx/tanx+tanx/tanx+tan^3x/tanx

= cotxsinx+1+tan^2x

= (cosx/sinx)sinx+sec^2x

= cosx+sec^2x

= Right hand side

answered Nov 20, 2013 by william Mentor

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