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Verify the proof: (secx+tanx)/(cscx+1)=tanx.

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thank you
asked Feb 12, 2014 in TRIGONOMETRY by mathgirl Apprentice

1 Answer

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Left hand side identity

= (Secx+Tanx)/(Cscx+1)

= [1/Cosx+Sinx/Cosx]/[1/Sinx+1}

= [1+Sinx/Cosx]/[1+Sinx/Sinx]

= Sinx/Cosx

= Tanx

= Right hand side identity.

answered Feb 12, 2014 by friend Mentor

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