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Mathematics: find the equation?

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what's the equation of a line through (4,-1) and whose segment intercepted between the axes in the 4th quadrant is equal to 2sqrt (17)?
asked Nov 27, 2013 in ALGEBRA 1 by anonymous Apprentice

1 Answer

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Slope-intercept form line equation is y = mx + b, where m is slope and b is y-intercept.

Here line crossing axes in the 4th quadrant. So, the y-intercept is -2√17

The line equation is y = mx - 2√17

Find the slope by substituing the point (4, -1)

-1 = m * 4 - 2√17

m = (2√17 -1)/4

The line equation is y = (2√17 -1)/4 x - 2√17

 

answered Nov 27, 2013 by steve Scholar

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