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if y=12 when x=18, find x when y=-16

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direct variation equation that relate x and y for algebra 1.

asked Nov 27, 2013 in ALGEBRA 1 by angel12 Scholar

2 Answers

0 votes

y = 12 when x = 18

Direct variation equation is y = kx.

The given numbers form one ratio expressed as y/x = 12/18

To find x, when y = -16

we set up another ratio -16/x

By the definition both ratios are equal 12/18 = -16/x

Divide each side by negitive 16.

(12/18)/-16 = (-16/-16x)

0.66/-16 = x

 -0.04125 = x

x = -0.04125

 

answered Nov 28, 2013 by william Mentor
edited Nov 28, 2013 by william

The value of x  = -24.

0 votes

y = 12 when x = 18

Direct variation equation is y = kx.

The given numbers form one ratio expressed as y/x = 12/18

To find x, when y = -16

we set up another ratio -16/x

By the definition both ratios are equal 12/18 = -16/x

Divide each side by negitive 16.

(12/18)/-16 = (-16/-16x)

1/-24 =1/x

x = - 24

answered Nov 28, 2013 by william Mentor

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