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Solve for Y, need help problem.?

+1 vote

y/4-3/2<y/2+1

asked Jan 17, 2013 in ALGEBRA 1 by anonymous Apprentice

1 Answer

+1 vote

y/4 - 3/2 < y/2 + 1

Subtract 'y/4' from each side.

y/4 - 3/2 - y/4 < y/2 + 1 - y/4

Simplify

-3/2 < y/2 - y/4 + 1

- 3/2 < (2y - y) / 4 + 1                  here 2 , 4 LCM is 4

Simplify

- 3/2 < (y/4) + 1.

Subtract 1 from each side.

- 3/2 - 1 < (y/4) + 1 -1

Simplify

(-3-2)/2 < y/4                          here 1 , 2 LCM is 2

-5/2 < y/4

Multiply each side by 4.

(-5/2) (4) < (y/4)(4)

Simplify

-10 < y

There fore

y > -10 .

answered Jan 17, 2013 by richardson Scholar

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