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Find the slope and y-intercept of the graph of each equation for:

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(2/3)x + (1/6)y = 2.
asked Mar 13, 2014 in PRE-ALGEBRA by linda Scholar

1 Answer

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Write the equation in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

The equation is  (2/3)x + (1/6)y = 2

Subtract (2/3)x to each side.

(1/6)y = 2 - (2/3)x

Multiply 6 to each side.

y = 12 - 4x

y = - 4x + 12.

Compare the equation with slope-intercept form y = mx + b.

slope = - 4 and y-intercept is 12.

y-intercept is 12, so the line crosses the y-axis at (0, 12)

Using slope find the next point.

Slope = rise/run = - 4/1

Start at point (0, 12), move 4 units down and 1 unit right, then plot the point (2, 4).

Draw a line through these points.

Graph :

graph for the equation - x - 2y = 8

 

answered Mar 13, 2014 by dozey Mentor

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