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How do I write this complex fraction in standard form?

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6/(4-13i)

complex_numbers

asked Jun 26, 2014 in PRECALCULUS by anonymous

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1 Answer

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The expression is .

Multiply the numerator and denominator by the conjugate of dnominator to rationalize the denominator.

The conjugate of 4 - 13i is 4 + 13i.

Denominator is in the form (a - b)(a + b) which is equal to a^2 - b^2.

Split the terms.

is the answer in standard form.

answered Jun 26, 2014 by joly Scholar

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