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(6x+9)(x^2-4x+3)?

asked Jul 23, 2014 in ALGEBRA 1 by anonymous

1 Answer

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The expression is (6x + 9)(x2 - 4x + 3)

= 6x(x2 ) + 6x( - 4x) + 6x(3) + 9(x2 ) +  9(- 4x) + 9(3)

Apply the product rule in exponents xm * xn = xm+n

= 6x2+1 - 24x1+1 + 18x + 9x2- 36x + 27

= 6x3 - 24x2 + 9x2 + 18x - 36x + 27

= 6x3  - 15x- 18x + 27

Product of (6x + 9)(x2 - 4x + 3) is 6x3 - 15x- 18x + 27.

answered Jul 23, 2014 by david Expert

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