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what is the quotient 6-x/x^2+2x-3 divided by x^2-4x-12/x^2+4x+3

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asked Jul 29, 2014 in ALGEBRA 2 by Don_n Rookie

1 Answer

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(6-x)/(x^2+2x-3) divided by (x^2-4x-12)/(x^2+4x+3)

Calculate the factors of the

x^2+2x-3 =x^2+3x-x-3

                = x(x+3)-1(x+3)

                     =(x+3)(x-1)

x^2-4x-12 = x^2-6x+2x-12

                   =x(x-6)+2(x-6)            

                    = (x-6)(x+2)

 

(x^2+4x+3)= x^2+3x+x+3

                   =x(x+3)+1(x+3)            

                    = (x+3)(x+1)

Simplify the expression:

image

 

answered Jul 29, 2014 by bradely Mentor

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