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Divide 8x^2 - 6^x - 20 by x – 2. Find the quotient and remainder.

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Divide 8x2 - 6x - 20 by x – 2. Find the quotient and remainder. 
A. 8x – 10; 0
B. 8x + 10; 0
C. 8x – 6; 3
D. 8x – 3; –3

 

asked Sep 3, 2014 in ALGEBRA 2 by tonymate Pupil

1 Answer

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Best answer

Use synthetic division to find image.

The dividend is 8x2 - 6x - 20, and the root is 2.

Step 1 : Write the terms of the dividend so that the degrees of the terms are in descending order. Then write just the coefficients as shown below.

image

Step 2 : Write the constant r of the divisor (x - r) to the left. In this case, r = 2. Bring the first coefficient, 8, down.

image

Step 3 : Multiply the first coefficient by r : (2)(8) = 16. Write the product under the second coefficient, - 6. Then add the product and the second coefficient, - 6 : - 6 + 16 = 10.

image

Step 4 : Multiply the sum, 10, by r : (2)(10) = 20.

Write the product under the next coefficient, - 20 and add : - 20 + 20 = 0. The remainder is 0.

image

The numbers along the bottom row are the coefficients of the quotient. Start with the power of x that is one less than the degree of the dividend. Thus, the quotient is 8x + 10.

image.

The option B is correct.

answered Sep 3, 2014 by casacop Expert
selected Sep 3, 2014 by tonymate

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