Use long division to find the quotient and remainder?

Use long division to find the quotient and remainder when f(x)=9 x^5 - 1 x^4 - 1 x^3 - 1 x^2 - 3 x - 5 is divided by g(x)=9 x^2 - 6 x + 4.

f(x)/g(x)

Rewrite the expression in long division form (9x5 - x4 - x3 - x2 - 3x - 5)/(9x2- 6x + 4).

Divide the first term of the dividend by the first term of the divisor 9x5/9x2= x3.

So, the first term of the quotient is x3. Multiply (9x2- 6x + 4) by x3 and subtract.

Divide the first term of the last row by first term of the divisor 5x4/9x2 = 5x2/9

So,the second term of the quotient is 5x2/9. Multiply (9x2- 6x + 4) by 5x2/9 and subtract.

Divide the first term of the last row by first term of the divisor  (-5x3/3)/9x2 = - 5x/27.

So,the third term of the quotient is (- 5x/27). Multiply (9x2- 6x + 4) by (- 5x/27) and subtract.

Divide the first term of the last row by first term of the divisor (- 39x2/9)/9x2 = -39/81.

So,the fourth term of the quotient is - 39/81. Multiply (9x2- 6x + 4) by (- 39/81) and subtract.

Quotient is

And the remainder is

.