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Quotient?? Divisor?

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what's the divisor and quotient of this problem?

(3x^3+2x^2-6x+4 )/ (x+1)
asked Oct 25, 2014 in TRIGONOMETRY by anonymous

1 Answer

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Rewrite the expression in long division form (3x3 + 2x2 - 6x + 4)/(x + 1).

Divide the first term of the dividend by the first term of the divisor 3x3/x = 3x2.

So,the first term of the quotient is 3x2. Multiply (x + 1) by 3x2 and subtract.

image

Divide the first term of the last row by first term of the divisor -x2/x = -x.

So,the second term of the quotient is -x. Multiply (x + 1) by (-x) and subtract.

image

Divide the first term of the last row by first term of the divisor  (- 5x)/x = - 5.

So,the third term of the quotient is (- 5). Multiply (x + 1) by (- 5) and subtract.

image

The remainder is the last entry in the last row.There fore, R = 9.

image.

The divisor d(x) = x + 1 and quotient q(x) = 3x² - x - 5.

answered Oct 25, 2014 by casacop Expert

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