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Divide using long division?

0 votes
27x^4+9x^3+6x^2/3x^2+2
State the quotient and remainder
asked Oct 31, 2014 in ALGEBRA 2 by anonymous
reshown Oct 31, 2014 by bradely

1 Answer

0 votes

The expression

image

Divide the first term of the dividend by the first term of the divisor 27x4/3x2 = 9x2.

So,the first term of the quotient is 9x2.Multiply (3x2 + 2) by 9x2 and subtract.

image

Divide the first term of the last row by first term of the divisor 9x3/3x2 = 3x.

So,the second term of the quotient is 3x. Multiply (3x2 + 2) by 3x and subtract.

image

Divide the first term of the last row by first term of the divisor  (- 12x2)/3x2 = - 4.

So,the third term of the quotient is (- 4). Multiply (3x2 + 2) by (- 4) and subtract.

image

Quotient is 9x2 + 3x - 4 and remainder is - 6x + 8.

answered Oct 31, 2014 by david Expert

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