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if the surface area of a sphere is increases by 44%, find the %increase in its diameter

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asked Feb 28, 2013 in BASIC MATH by Afeez Novice

1 Answer

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Best answer

Surface Area of a Sphere (A) = 4πr 2

Area is directly proportional to r2. So, A2/A1 = r 22/ r 12

Area increased by 44% of its original area. So, A2 = 1.44A1

A2/A1 = r 22/ r 12

1.44/1 = r 22/ r 12

r 22 = 1.44 r 12

Take square root each side

r 2 = sqrt(1.44) r 1

r 2 = 1.2 r 1 = r 1 + 0.2 r 1

% increase in it's diameter is 20%.

answered Feb 28, 2013 by steve Scholar
selected Feb 28, 2013 by Afeez

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