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Calculus help.?

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Find dy/dx at x = 0

y = 2u / (1 - 4u), u = (5x^2 + 1)^4
asked Aug 22, 2014 in CALCULUS by anonymous

1 Answer

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The given equations are 

 

The derivative of given function at x=0  is '0'

answered Aug 22, 2014 by anonymous

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