Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

774,900 users

Find dy/dx Calculus help?

0 votes
y = 3 (tan x + sec x)(tan x - sec x)
asked Jul 2, 2013 in CALCULUS by skylar Apprentice

1 Answer

0 votes

Given that y = 3 (tan x + sec x)(tan x - sec x)

                    = 3(tan^2x - sec^2x)                                     [ Since (a + b) (a - b) = a^2 - b^2 ]

                    = 3tan^2x - 3sec^2x

Differenciating on both sides we get,

             dy/dx = d/dx(3tan^2x) - d/dx(3sec^2x)

                      = 3(2tanx)d/dx(tanx) - 3(2secx)d/dx(secx)  [ Using chain rule ]

                      = 6tanx(sec^2x) - 6secx(secxtanx)   [Since d/dx(tanx) = sec^2x, d/dx(secx) = secxtanx]

                      = 6tanxsec^2x - 6tanxsec^2x

                      = 0

Therefore dy/dx = 0

answered Jul 2, 2013 by joly Scholar

Related questions

asked Oct 24, 2014 in CALCULUS by anonymous
asked Nov 14, 2014 in CALCULUS by anonymous
asked Nov 13, 2014 in CALCULUS by anonymous
asked Nov 12, 2014 in CALCULUS by anonymous
asked Nov 3, 2014 in CALCULUS by anonymous
asked Oct 30, 2014 in CALCULUS by anonymous
asked Oct 21, 2014 in CALCULUS by anonymous
asked Oct 1, 2014 in CALCULUS by anonymous
asked Aug 22, 2014 in CALCULUS by anonymous
...