Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

774,874 users

The area of two rectangles is 360 square centimeters.

0 votes

The length of the second rectangle is 12 cm greater than the first while its width is

 5 cm less than the first. Find the difference of the perimeters of the two rectangles if the lengths and widths are positive integers.

 

asked Oct 11, 2014 in CALCULUS by anonymous

1 Answer

0 votes

Length of the first rectangle = x

Then length of second rectangle = x + 12

Width of first rectangle = y

Then width of second rectangle = y - 5

Perimeter of first rectangle(P₁) = 2(x + y)

P₁ = 2x + 2y

Perimeter of second rectangle(P₂) = 2(x + 12 + y - 5)

= 2x + 24 + 2y - 10

P₂ = 2x + 2y + 14

Difference = P₂ - P₁

= (2x + 2y + 14) - (2x + 2y)

= 2x + 2y + 14 - 2x - 2y

= 14

Difference of the perimeters is 14 cm.

answered Oct 11, 2014 by david Expert

Related questions

...