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What is the slope of (0,0) and (-1/2, 1/3)????

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I haven't done these in a while and having trouble with the fractions. Please help.

asked Mar 15, 2013 in ALGEBRA 1 by andrew Scholar

2 Answers

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The points are (0,0) and (-1 / 2 , 1 / 3)

(0,0) is the origin point

Two points (x1, y1) and (x2 , y2) are given then the slope is m = (y2 - y1) / (x2 - x1)

Substitute x1 = 0, y1 = 0, x2 = -1 / 2  and  y2 = 1 / 3

There fore m =[(1 / 3) - 0] / (- 1 / 2) - 0

Simplify

m = (1 / 3 ) / (- 1 / 2)

There fore m = - 2 / 3.

The slope is m = -2 / 3.

answered Mar 15, 2013 by diane Scholar
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Slope = rise / run = (y2-y1) / (x2-x1)

= (1/3 – 0) / ( -1/2 – 0)

= -2/3

answered Mar 15, 2013 by Justin Pupil

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