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Consider a force F=86.1 N pulling 3 blocks of masses m1=7.07 kg, m2=19.7 kg, and m3=37 kg

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along a frictionless horizontal surface. find the acceleration a of the blocks?

asked Nov 6, 2014 in PHYSICS by anonymous

1 Answer

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3 blocks of masses m1 = 7.07 kg , m2 = 19.7 kgs and m3 = 37 kg .

Total mass of 3 blocks is 7.07 + 19.7 + 37 = 63.77 kg

The force applied on 3 blocks is 86.1 N .

The acceleration of 3 blocks can be found by the formula F = ma .

 86.1 = (63.77)a 

a = 86.1 / 63.77

a = 1.35 m/s²

So the acceleration of 3 blocks is given by 1.35 m/s² .

answered Nov 6, 2014 by friend Mentor

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