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Please help me with physics?

0 votes

A 0.100 kg baseball is thrown upward with an initial speed of 16.0 m/s. 

(a) What is the force on the ball when it reaches half of its maximum height? (Disregard friction.) 




(b) What is the force on the ball when it reaches its peak? 

N

asked Nov 6, 2014 in PHYSICS by anonymous

2 Answers

0 votes

(a)

The mass of the baseball = 0.100 kg.

Force acting on the ball when ball reaches half of the maximum height is Force due to garvity.

Therefore Accerlation due to gravity is not dependent on the height.

F = mg

F = 0.100 * 9.8

F = 0.98 N

Therefore the Force acting on the ball when ball reaches half of the maximum height is 0.98 N.

answered Nov 6, 2014 by dozey Mentor
0 votes

(b)

The mass of the baseball = 0.100 kg.

Force acting on the ball when ball reaches to the peak is Force due to garvity.

Therefore Accerlation due to gravity is not dependent on the height.

Therefore Force is constant at any instant of height.

F = mg

F = 0.100 * 9.8

F = 0.98 N

Therefore the Force acting on the ball when ball reaches to the peak is 0.98 N.

answered Nov 6, 2014 by dozey Mentor

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