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Please help me out with this physics problem!?

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The critical angle for total internal reflection at a diamond-air boundary is 24.4 degrees. What is the angle of refraction in the air if light enters boundary at an angle of 20.0 degrees?

asked Nov 10, 2013 in PHYSICS by anonymous Apprentice

1 Answer

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sin(θ cri)=(nr/ni)

For air nr=1

sin(24.4)=(1/ni)

ni=2.42

From the Snell's law

(n1/n2 )=(sinθ2/sinθ1)

1/2.42=sinθ2/sin20

sinθ2=0.1413

θ2=8.123

Angle of refraction is 8.123

 

answered Nov 10, 2013 by bradely Mentor

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