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Dividing Rational Expressions

0 votes

equation

asked Jan 2 in ALGEBRA 1 by anonymous

1 Answer

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[(3a^2 - 3a - 36)/(2a^2 + 8a - 10)] / [(a^2 - a - 12)/(a^2 + 3a - 10)]

                =   [3(a^2 - a - 12)/2(a^2 + 4a - 5)] X [(a^2 + 3a - 10)/(a^2 - a - 12)]

                        =   3(a^2 + 3a - 10) / 2(a^2 + 4a - 5)

                        =   3(a^2 + 5a - 2a - 10) / 2(a^2 + 5a - a - 5)

                        =   3[ a(a + 5) - 2(a + 5) ] / 2[a(a + 5) - 1(a + 5)]

                        =   3[ (a + 5)(a - 2) ] / 2[a(a + 5) - 1(a + 5)]

                        =   3[ (a + 5)(a - 2) ] / 2[(a + 5)(a - 1)]

                        =   3(a - 2) / 2(a - 1)

Hence,

[(3a^2 - 3a - 36)/(2a^2 + 8a - 10)] / [(a^2 - a - 12)/(a^2 + 3a - 10)]   =   3(a - 2) / 2(a - 1)

 

answered Sep 28 by homeworkhelp Mentor
edited Sep 28 by bradely

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