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Is 8x+6y=-3 perpendicular, parallel, or neither compared with 3x-4y=-3

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this is a graph problem.
asked Mar 8, 2014 in ALGEBRA 2 by payton Apprentice

1 Answer

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Write the  equations in slope intercept form.

First equation is 8x +6y = -3

Subtract 8x  from each side.

6y  = -8x -3

Divide to each side by 6.

= (-4/3)x -3 ---> (1)

Secon equation 3x -4y  = -3

Subtract 3x from each side.

-4 = -3x -3

Divide to each side by negitive 4.

y  = (3/4)x +3/4 ---> (2)

Observe the lines slopes are negitive reciprocal to each other.

Given lines are perpendicular.

answered Mar 8, 2014 by ashokavf Scholar

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