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Find a point on the y-axis that is equidistant from the points (1, –7) and (5, –1)????

0 votes
a.
(–2, 0)
b.
(0, –2)
c.
(0, 0)
d.
(0, 3)
e.
(0, –4)
asked Mar 4, 2013 in ALGEBRA 1 by futai Scholar

1 Answer

0 votes

Distance formula  :    √(x₂ -x₁)2 +(y₂-y₁)2

Given points   (1,– 7) ,   (5,– 1)

b) (0,– 2)

Distance  between  (0,– 2) and (1,– 7)

      Formula  =√(x₂ -x₁)2 +(y₂-y₁)2

Substitute (0,– 2) and (1,– 7) in the formula

   √(1 –0)2 +(– 7–(– 2))2

  √(1)2 +(– 7+2))2

  √(1)2 +(– 5))2

  √1+25

   √26

Formula  =√(x₂ -x₁)2 +(y₂-y₁)2

Substitute (0,– 2) and (5,– 1) in the formula

        √(5 –0)2 +(– 1–(– 2))2

    √(5 )2 +(– 1+2)2

     √25 + 1

     √26

Option b is right choice.
 

 

 

 

 

answered Mar 7, 2013 by hussy Rookie

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