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Dividing polynomials?(x^3-19x-30) ÷ (x+3)

0 votes
please include steps on how to do this with long division.. please I need help quick. thank you!
asked Dec 27, 2012 in ALGEBRA 1 by chrisgirl Apprentice

1 Answer

+1 vote
Given  funtion=x^3-19x-30 / x+3

        x+3)x^3-19x-30(x^2-3x-10

             (-)x^3+3x^2

             --------------

              -3x^2-19x-30

          (+)-3x^2-9x

           ---------------

          -10x-30

           10x+30

           ---------

               0

          -----------

    x^3-19x-30 / x+3 = x^2-3x-10

    x^2-3x-10=x^2+2x-5x-10

                 =x(x+2)-5(x+2)

                 =(x+2) (x-5)

 x^3-19x-30 / (x+3) = (x+2) (x-5)
answered Dec 27, 2012 by ricky Pupil

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