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Complex number multiplication?

0 votes
find z such that (4+2i)z=3-2i
asked Apr 9, 2013 in ALGEBRA 2 by andrew Scholar

1 Answer

0 votes

(4 + 2i)z = 3 - 2i

Multiply each side  by 4 - 2i 

(4 - 2i)(4 + 2i)z =(4 - 2i)(3 - 2i)

Recall : (a - b)(a + b) = (a2 - b2)

(16 - 4i2)z = (12 - 14i + 4i2)

Substitute i2 = -1 in the  above equation

(16 - 4(-1))z = (12 - 14i  +4(-1))

20z = 8 - 14i

Divide each side by 20

z = (8 - 14i) / 20.

 

answered Apr 10, 2013 by diane Scholar

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