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Solve the equation!!!!!!!!!!!!!!!!!!!!!!!

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x^2/3 - 2x^1/3 - 8 = 0

asked Jun 20, 2013 in ALGEBRA 2 by skylar Apprentice

2 Answers

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The given equation x^2/3 - 2x^1/3 - 8 = 0

Let y =x^1/3

y^2 +2y - 8 = 0

y^2 + 4y - 2y - 8 =0

( y+4) (y -2) = 0

y = - 4, y = 2

Now we have

x^1/3 = - 4 and x^1/3 = 2

Therefore x = - 64  and x = 8 .

answered Jun 20, 2013 by goushi Pupil
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solution to the equation is

solution to the x^2/3 - 2x^1/3 - 8 = 0

answered Jun 26, 2013 by Naren Answers Apprentice

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