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Linear Equations in Two Variables

0 votes
Directions:

Use the intercept form to find the equation of the line with the given intercepts. The intercept form of the equation of a line with intercepts (a,0) and (0,b) is

(x/a)+(y+b)=1, a=/=0, b=/=0

Problems:

68) x-intercept: (2,0)
y-intercept: (0,3)

72) point on line: (1,2)
x-intercept: (c,0)
y-intercept: (o,c), c=/=0
asked Oct 25, 2013 in ALGEBRA 2 by abstain12 Apprentice
edited Oct 26, 2013 by moderator

1 Answer

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Intercept - form of line equation is (x/a) + (y/b) = 1, where a is x - intercept and b is y - intercept.

68).

x - intercept : (a, 0) = (2, 0), and

y - intercept : (0, b) = (0, 3).

Substitute corresponding values in intercept - form.

(x/2) + (y/3) = 1.

Therefore, the line equation in intercept - form is (x/2) + (y/3) = 1.

72).

Let, the point on line : (x, y) = (1, 2),

x - intercept : (a, 0) = (c, 0), and

y - intercept : (0, b) = (0, c), c=/=0.

Substitute the corresponding values in intercept - form.

(1/c) + (2/c) = 1

(1 + 2) / c = 1

3 / c = 1

c = 3.

Now, the line equation is x/3 + y/3 = 1.

Therefore, the line equation in intercept - form is (x/3) + (y/3) = 1.

answered Aug 17, 2014 by lilly Expert

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