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What is the slope-intercept form, slope, and y-intercept for x-5y=10?

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x-5y=10 is the starting equation

asked Nov 27, 2013 in ALGEBRA 1 by linda Scholar

1 Answer

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x-5y = 10

subtract  x from each side.

x-5y-x = 10-x

-5y = -x+10

Divide to each side by negitive 5.

-5y/-5 = (-x+10)/-5

y = (1/5)x-2

Compare it to slope intercept form y = mx+b.

slope is 1/5 and y intercept is -2.

answered Nov 27, 2013 by william Mentor

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