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solve the system using the elimination method

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3x-4y=-11

6x+2y=28

asked Dec 4, 2013 in ALGEBRA 1 by harvy0496 Apprentice

1 Answer

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Eliminaion method

3x-4y = -11----------> (1)

6x+2y = 28

Muliple to each side of above equation by 2.

12x+4y = 56 ---------> (2)

To eliminae the y value add the equaions (1) and (2).

3x-4y = -11

12x+4y = 56

__________

15x = 45

Divide to each side by 15.

15x/15 = 45/15

x = 3

Substitute the x value in (1).

3*3-4y = -11

9-4y = -11

Subtract 9 from each side.

9-9-4y = -11-9

-4y = -20

Divide to each side by negitive 4.

-4y/-4 = -20/-4

y = 5

Solution x =3, y = 5.

 

answered Dec 4, 2013 by william Mentor

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